2(2^2x)=4^x+64

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Solution for 2(2^2x)=4^x+64 equation: 



2(2^2x)=4^x+64

We move all terms to the left:

2(2^2x)-(4^x+64)=0

We get rid of parentheses

22^2x-4^x-64=0

We move all terms containing x to the left, all other terms to the right

22^2x-4^x=64

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